A serial dilution is any dilution in which the concentration decreases by the same factor in each successive step. In serial dilutions, you multiply the dilution factors for each step. The dilution factor or the dilution is the initial volume divided by the final volume.

Feb 17, 2016  A very quick lesson on how to do the math for serial and simple dilutions. Skip navigation Sign in. Serial dilutions lesson Kim Wiest. Liters Volume Calculations Chemistry - Duration. A serial dilution is any dilution in which the concentration decreases by the same factor in each successive step. In serial dilutions, you multiply the dilution factors for each step. The dilution factor or the dilution is the initial volume divided by the final volume.

#DF = V_i/V_f# For example, if you add a 1 mL sample to 9 mL of diluent to get 10 mL of solution, #DF = V_i/V_f# = #(1'mL')/(10'mL') = 1/10#. This is a 1:10 dilution. Example 1 What is the dilution factor if you add 0.2 mL of a stock solution to 3.8 mL of diluent? #V_f# = 0.2 mL + 3.8 mL = 4.0 mL #DF = V_i/V_f# = #(0.2'mL')/(4.0'mL') = 1/20#.

This is a 1:20 dilution. Voennaya forma novogo obrazca dlya fotoshopa. Example 2 If you did the above dilution four times, what would be the final dilution factor? Solution 2 Remember that serial dilutions are always made by taking a set quantity of the initial dilution and adding it successively to tubes with the same volume.

So you multiply each successive dilution by the dilution factor. You would transfer 0.2 mL from Tube 1 to 3.8 mL of diluent in Tube 2 and mix.

Then transfer 0.2 mL from Tube 2 to 3.8 mL of diluent in Tube 3 and mix. Repeat the process until you have four tubes. The dilution factor after four dilutions is #DF = 1/20 × 1/20 × 1/20 × 1/20 = 1/160000# = 1:160 000 If the concentration of the original stock solution was 100 µg/µL, the concentration in Tube 4 would be 100 µg/µL × #1/160000# = 6.25 × 10⁻⁴ µg/µL Hope this helps.